2x^2+15x-5.3=0

Solution for 2x^2+15x-5.3=0 equation:

2x^2+15x-5.3=0

a = 2; b = 15; c = -5.3;
Δ = b2-4ac
Δ = 152-4·2·(-5.3)
Δ = 267.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-\sqrt{267.4}}{2*2}=\frac{-15-\sqrt{267.4}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+\sqrt{267.4}}{2*2}=\frac{-15+\sqrt{267.4}}{4}
$